3(x+2)^2+6=122

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Solution for 3(x+2)^2+6=122 equation: 



3(x+2)^2+6=122

We move all terms to the left:

3(x+2)^2+6-(122)=0

We add all the numbers together, and all the variables

3(x+2)^2-116=0

We move all terms containing x to the left, all other terms to the right

3(x+2)^2=116

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